Optimal. Leaf size=142 \[ \frac{2^{-m-1} \left (-4 m^3+390 m^2-8324 m+27783\right ) (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (2 x+1))}{27 (1-m) m}-\frac{(3 x+2)^{m+1} \left (4 m^2-4 (109-2 m) m x-512 m+9261\right ) (2 x+1)^{-m}}{27 m}-\frac{2}{9} (5-4 x)^2 (3 x+2)^{m+1} (2 x+1)^{-m} \]
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Rubi [A] time = 0.434518, antiderivative size = 142, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.115 \[ \frac{2^{-m-1} \left (-4 m^3+390 m^2-8324 m+27783\right ) (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (2 x+1))}{27 (1-m) m}-\frac{(3 x+2)^{m+1} \left (4 m^2-4 (109-2 m) m x-512 m+9261\right ) (2 x+1)^{-m}}{27 m}-\frac{2}{9} (5-4 x)^2 (3 x+2)^{m+1} (2 x+1)^{-m} \]
Antiderivative was successfully verified.
[In] Int[(5 - 4*x)^3*(1 + 2*x)^(-1 - m)*(2 + 3*x)^m,x]
[Out]
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Rubi in Sympy [A] time = 27.1491, size = 110, normalized size = 0.77 \[ - \frac{2 \left (- 4 x + 5\right )^{2} \left (2 x + 1\right )^{- m} \left (3 x + 2\right )^{m + 1}}{9} - \frac{\left (2 x + 1\right )^{- m} \left (3 x + 2\right )^{m + 1} \left (64 m^{2} - 64 m x \left (- 2 m + 109\right ) - 8192 m + 148176\right )}{432 m} + \frac{2^{- m} \left (2 x + 1\right )^{- m + 1} \left (- 4 m^{3} + 390 m^{2} - 8324 m + 27783\right ){{}_{2}F_{1}\left (\begin{matrix} - m, - m + 1 \\ - m + 2 \end{matrix}\middle |{- 6 x - 3} \right )}}{54 m \left (- m + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((5-4*x)**3*(1+2*x)**(-1-m)*(2+3*x)**m,x)
[Out]
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Mathematica [C] time = 1.66145, size = 395, normalized size = 2.78 \[ \frac{7}{4} \left (\frac{483 (5-4 x)^2 (8 x+4)^{-m} (12 x+8)^m F_1\left (2;-m,m;3;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )}{483 F_1\left (2;-m,m;3;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )+m (4 x-5) \left (21 F_1\left (3;1-m,m;4;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )-23 F_1\left (3;-m,m+1;4;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )\right )}-\frac{23\ 2^{m+3} (4 x-5)^3 (3 x+2)^m (4 x+2)^{-m} F_1\left (3;-m,m;4;-\frac{3}{23} (4 x-5),\frac{1}{7} (5-4 x)\right )}{3 \left (644 F_1\left (3;-m,m;4;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )+m (4 x-5) \left (21 F_1\left (4;1-m,m;5;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )-23 F_1\left (4;-m,m+1;5;\frac{3}{23} (5-4 x),\frac{1}{7} (5-4 x)\right )\right )\right )}+\frac{7\ 2^{2-m} (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-6 x-3)}{m-1}-\frac{196 (-6 x-3)^m (3 x+2)^{m+1} (2 x+1)^{-m} \, _2F_1(m+1,m+1;m+2;6 x+4)}{m+1}\right ) \]
Warning: Unable to verify antiderivative.
[In] Integrate[(5 - 4*x)^3*(1 + 2*x)^(-1 - m)*(2 + 3*x)^m,x]
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Maple [F] time = 0.084, size = 0, normalized size = 0. \[ \int \left ( 5-4\,x \right ) ^{3} \left ( 1+2\,x \right ) ^{-1-m} \left ( 2+3\,x \right ) ^{m}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((5-4*x)^3*(1+2*x)^(-1-m)*(2+3*x)^m,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ -\int{\left (3 \, x + 2\right )}^{m}{\left (2 \, x + 1\right )}^{-m - 1}{\left (4 \, x - 5\right )}^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-(3*x + 2)^m*(2*x + 1)^(-m - 1)*(4*x - 5)^3,x, algorithm="maxima")
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (-{\left (64 \, x^{3} - 240 \, x^{2} + 300 \, x - 125\right )}{\left (3 \, x + 2\right )}^{m}{\left (2 \, x + 1\right )}^{-m - 1}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-(3*x + 2)^m*(2*x + 1)^(-m - 1)*(4*x - 5)^3,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((5-4*x)**3*(1+2*x)**(-1-m)*(2+3*x)**m,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int -{\left (3 \, x + 2\right )}^{m}{\left (2 \, x + 1\right )}^{-m - 1}{\left (4 \, x - 5\right )}^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(-(3*x + 2)^m*(2*x + 1)^(-m - 1)*(4*x - 5)^3,x, algorithm="giac")
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